现在界面已经完成了，
刚刚完成了禁手算法，把代码共享出来：
Code
private function IsForbidden(x:int, y:int, board:Array):int 
{
var index:int = x*15+y; // set this position(x,y) to black. board[index] = CellType.BLACK; // 1st check whether there is overline. var array:Array =this.GetAnalyseArray(x,y,board); 
if(this.IsOverline(array)) {
board[index] = CellType.EMPTY; return ResultType.OVERLINE;
} // use recursion to check whether there is double-4 or double-3. // the check methord is count the open 3 and open 4's count, // if one of them larger than 1 so is a forbidden. var count3:int = 0; var count4:int = 0; var i, j:int = 0; for(i=0; i<4; i++) {
// calculate open 4's count. for(j=3; j<7; j++) {
// patten: ?0x000? if(array[i][j]==CellType.BLACK&&this.IsEmpty(i,j+1,array)&& array[i][j+2]==CellType.BLACK&&array[i][j+3]==CellType.BLACK&& array[i][j+4]==CellType.BLACK&& this.IsNotBlack(i,j-1,array)&&this.IsNotBlack(i,j+5,array)) {
count4++; continue; } // patten: ?00x00? if(array[i][j]==CellType.BLACK&&array[i][j+1]==CellType.BLACK&& this.IsEmpty(i,j+2,array)&&array[i][j+3]==CellType.BLACK&& array[i][j+4]==CellType.BLACK&& this.IsNotBlack(i,j-1,array)&&this.IsNotBlack(i,j+5,array)) {
count4++; continue; } // patten: ?000x0? if(array[i][j]==CellType.BLACK&&array[i][j+1]==CellType.BLACK && array[i][j+2]==CellType.BLACK&&this.IsEmpty(i,j+3,array) && array[i][j+4]==CellType.BLACK&& this.IsNotBlack(i,j-1,array)&&this.IsNotBlack(i,j+5,array)) {
count4++; continue; } // patten: ??0000?? // not like above three, this check index is the above index plus 1. // in other words, the check index is 4 to 8 and above index is 3 to 7. if(array[i][j+1]==CellType.BLACK&&array[i][j+2]==CellType.BLACK&& array[i][j+3]==CellType.BLACK&&array[i][j+4]==CellType.BLACK) {
if(this.IsEmpty(i,j,array)&&this.IsNotBlack(i,j-1,array)&&this.IsNotBlack(i,j+5,array)) {
count4++; continue; } if(this.IsEmpty(i,j+5,array)&&this.IsNotBlack(i,j+4,array)&&this.IsNotBlack(i,j,array)) {
count4++; continue; } } } var tmpIndex:int; // calculate open 3's count for(j=4; j<7; j++) {
// patten: ??0x00?? if(array[i][j]==CellType.BLACK&&this.IsEmpty(i,j+1,array)&& array[i][j+2]==CellType.BLACK&&array[i][j+3]==CellType.BLACK&& this.IsEmpty(i,j-1,array)&&this.IsEmpty(i,j+4,array)&& (this.IsNotBlack(i,j-2,array)||this.IsNotBlack(i,j+5,array))) {
tmpIndex = this.IndexConverter(i,j+1,x,y); if(this.IsForbidden(Math.floor(tmpIndex/15),tmpIndex%15,board)==ResultType.NOTHING){
count3++; } continue; } // patten: ??00x0?? if(array[i][j]==CellType.BLACK&&array[i][j+1]==CellType.BLACK&& this.IsEmpty(i,j+2,array)&&array[i][j+3]==CellType.BLACK&& this.IsEmpty(i,j-1,array)&&this.IsEmpty(i,j+4,array)&& (this.IsNotBlack(i,j-2,array)||this.IsNotBlack(i,j+5,array))) {
tmpIndex = this.IndexConverter(i,j+2,x,y); if(this.IsForbidden(Math.floor(tmpIndex/15),tmpIndex%15,board)==ResultType.NOTHING) { count3++; } continue; } // patten: ??000?? if(array[i][j]==CellType.BLACK&&array[i][j+1]==CellType.BLACK&&array[i][j+2]==CellType.BLACK) {
if(this.IsEmpty(i,j-2,array)&&this.IsEmpty(i,j-1,array)&& this.IsEmpty(i,j+3,array)&&this.IsNotBlack(i,j-3,array)) {
tmpIndex = this.IndexConverter(i,j-1,x,y); if(this.IsForbidden(Math.floor(tmpIndex/15),tmpIndex%15,board)==ResultType.NOTHING) {
count3++; continue; } } if(this.IsEmpty(i,j-1,array)&&this.IsEmpty(i,j+3,array)&& this.IsEmpty(i,j+4,array)&&this.IsNotBlack(i,j+5,array)) {
tmpIndex = this.IndexConverter(i,j+3,x,y); if(this.IsForbidden(Math.floor(tmpIndex/15),tmpIndex%15,board)==ResultType.NOTHING) {
count3++; continue; } } } } } // reset the position to empty and return result. board[index] = CellType.EMPTY; if(count3>1) {
return ResultType.DOUBLE_THREE; } if(count4>1) {
return ResultType.DOUBLE_FOUR; } return ResultType.NOTHING;
}
就是通过一个递归判断是否当前下子为禁手。
测试后发现可以判断复杂的禁手，如：
